.5x^2+x-12=0

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Solution for .5x^2+x-12=0 equation: 



.5x^2+x-12=0

a = .5; b = 1; c = -12;
Δ = b2-4ac
Δ = 12-4·.5·(-12)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-5}{2*.5}=\frac{-6}{1}
=-6
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+5}{2*.5}=\frac{4}{1}
=4
$

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